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19 August, 07:07

A jet travels 2250 km westward at a speed of 960 km/hr. it then encounters a strong headwind and its speed drops to 805 km/hr for the next 1320 km of its westward trip. what is the average velocity for the trip?

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  1. 19 August, 08:52
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    For the first part of the trip:

    we have velocity = 960 km/hr and distance = 2250 km

    velocity = distance / time

    time1 = distance / velocity = 2250 / 960 = 2.34375 hours

    For the second part of the trip:

    we have velocity = 805 km/hr and distance = 1320 km

    velocity = distance / time

    time2 = distance / velocity = 1320 / 805 = 1.63975 hours

    For the total trip:

    we have:

    total distance covered = 2250 + 1320 = 3570 km

    total time taken = 2.34375 + 1.63975 = 3.9835 hours

    average velocity = total distance / total time

    average velocity = 3570 / 3.9835 = 896.1968 km/hr
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