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8 March, 14:59

How many molecules are there in 4.00 l of oxygen gas at 500.∘ c and 50.0 torr?

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  1. 8 March, 18:51
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    From the ideal gas law

    pv=nRT, n is therefore PV/RT

    R is the

    R is gas constant = 62.364 torr/mol/k

    P=500torr

    V=4.00l

    T=500+273=773k

    n={ (500 torr x 4.00l) / (62.364 x773k) }=0.041moles

    the number of molecules=moles x avorgadro costant that is 6.022x10^23)

    6.022 x 10^23) x0.041=2.469 x10^22molecules
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