A 100 g piece of aluminum is heated to 90°C. It is then dropped into water to bring its temperature down to 20°C. The heat transferred to water is 6300 J. What is the specific heat capacity of aluminum?

0.90 J/g°C

Explanation:

The specific heat capacity is the ratio of the heat transferred to the product of the mass of the object and the change in temperature. So the specific heat capacity of aluminum is 6300 / (100 * 70) = 0.90 J/g°C.

c = 0.9 j/g. °C

Explanation:

Given dа ta:

Mass of aluminium = 100 g

Initial temperature = 90 °C

Final temperature = 20°C

Heat transfer = 6300 J

Specific heat of aluminium = ?

Solution:

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

The Q will negative because metal release the heat.

c = Q / m. ΔT

ΔT = t2 - t1

ΔT = 20°C - 90 °C

ΔT = - 70 °C

c = - 6300 j / 100 g.-70°C

c = - 6300 j / - 7000 g.°C

c = 0.9 j/g. °C