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11 October, 23:41

The solubility of a gas in water is 0.22 g/L at 20.0 kPa of pressure. What is the solubility when the pressure is increased to 115 kPa?

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  1. 11 October, 23:53
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    Solubility is 1.265g/L

    Explanation:

    According to Henry's law which states that the solubility of a gas in liquid is directly proportional to the pressure of the gas above the solution.

    Sg1 / P1 = Sg2 / P2,

    where Sg is the gas solubility, P is the gas pressure.

    Sg1 = 0.22

    P1 = 20kPA

    P2 = 115kPA

    Sg2 = ?

    Sg2 = Sg1 P2 / P1

    Sg2 = 0.22 * 115*10^3 / 20*10^3

    Sg2 = 25.3*10^3 / 20*10^3

    Sg2 = 1.265g/L

    the solubility of the gas in water at the new pressure is 1.265g/L
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