43.0 grams of potassium chloride dissolves in 600 mL of water. What is the concentration of the solution?

Answer: 0.96M

Explanation:

Potassium chloride has a chemical formula of KCl.

Mass of KCl = 43.0 grams

Amount of moles of KCl (n) = ?

Use the molar mass of KCl to get the amount in moles.

The atomic masses of Potassium = 39g;

and Chlorine = 35.5g

So, KCl = 39g + 35.5g

= 74.5g/mol

Then, apply the formula

Number of moles = mass in grams / molar mass

n = 43.0g / 74.5 g/mol

n = 0.577 moles

Now, given that

Volume of water (v) = 600mL

[convert 600mL to liters

If 1000mL = 1 liter

600mL = 600/1000 = 0.6 liters]

Concentration of solution (c) = ?

Amount of moles of KCl (n) =

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

c = 0.577 moles / 0.6 liters

c = 0.96M

Thus, the concentration of the solution is acidic 0.96M

0,9613 mol/dm^3

Explanation:

Molarmass of KCl is 74,55 g/mol. So 43grams of it is 43/74,55=0,5768 mol.

Density of water is ususally 1g/cm^3. So 600ml=600cm^3=0,6dm^3.

You have 0,5768 mol of stuff in 0,6dm^3 water. If the question refers to conventional mol/cm^3 concentration, then you need to find out how much stuff is in 1dm^3 water, you do that by (1/0,6) * 0,5768=0,96133