If 32.78 ml of naoh solution is required to neutralize 20.00 ml 0f 0.2500 m of sulfuric acid, h2so4 (aq), what is the concentration of the naoh solution? the balanced equation is: 2naoh (aq) + h2so4 (aq) → na2so4 (aq) + 2h2o (l)

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Chemistry

Alisha Moody

8 December, 15:07

If 32.78 ml of naoh solution is required to neutralize 20.00 ml 0f 0.2500 m of sulfuric acid, h2so4 (aq), what is the concentration of the naoh solution? the balanced equation is: 2naoh (aq) + h2so4 (aq) → na2so4 (aq) + 2h2o (l)

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Tori · Answer 1

The concentration of the NaOH solution is 0.3051 mol/L.

Step 1. Calculate the moles of H_2SO_4

Moles of H_2SO_4

= 20.00 mL H_2SO_4 * (0.2500 mmol H_2SO_4/1 mL H_2SO_4)

= 5.000 mmol H_2SO_4

Step 2. Calculate the moles of NaOH

Moles of NaOH = 5.000 mmol H_2SO_4 * (2 mmol NaOH / 1 mmol H_2SO_4)

= 10.00 mmol NaOH

Step 3. Calculate the concentration of the NaOH

c = moles/litres = 10.00 mmol/32.78 mL = 0.3051 mol/L