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30 November, 20:35

Find all the values of x for which the function is differentiable.

f (x) = (x^3-8) / (x^2-4x-5)

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  1. 30 November, 22:27
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    The function is differentiable for:

    x² - 4 x - 5 ≠ 0

    x² - 5 x + x - 5 ≠ 0

    x (x - 5) + (x - 5) ≠ 0

    (x - 5) (x + 1) ≠ 0

    x ≠ 5 and x ≠ - 1

    Answer: x ∈ R / { - 1, 5 }
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