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18 December, 14:32

A rectangular garden has a perimeter of 54 feet. it's length is 3 less than twice its width. write and solve an equation to solve for the gardens dimensions

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  1. 18 December, 17:01
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    2 (L+W) = 54

    L=2W-3

    Substitute L in the first equation:

    2 ((2W-3) + W) = 54.

    Divide by 2:

    (2W-3) + W=27

    Simplify by collecting like terms:

    3W-3=27.

    Add 3:

    3W=30.

    Divide by 3 to get that

    W=10.

    Substitute the L and W relations to get

    L=2W-3

    L=2*10-3

    L=17.

    The answers are length is 17 and width is 10.
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