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15 February, 05:26

A lightbulb has a resistance of 285 ω when operating with a potential difference of 110 v across it. what is the current in the lightbulb?

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  1. 15 February, 06:01
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    Current = voltage / resistance

    = 110 v / 285 Ω

    = 0.386 Ampere (rounded)
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