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14 March, 15:33

A rectangular loop of wire carrying a 4.0-A current is placed in a magnetic field of 0.60 T. The magnitude of the torque acting on this wire when the plane of the loop makes a 30° angle with the field is measured to be 1.1 N · m. What is the area of this loop?

a) 0.20 m2

b) 0.53 m2

c) 0.26 m2

d) 0.80 m2

e) 0.40 m2

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Answers (2)
  1. 14 March, 16:34
    0
    b) A = 0.52 m²

    Explanation:

    Given that

    I = 4 A

    B = 0.6 T

    θ=90° - 30° = 60°

    T = 1.1 N. m

    We know that torque T given as

    T = I B A sinθ

    Now by putting the values

    T = I B A sinθ

    1.1 = 4 x 0.6 x A x sin 60°

    A = 0.52 m²
  2. 14 March, 18:11
    0
    option B

    Explanation:

    given,

    rectangular loop carrying current (I) = 4 A

    magnetic field (B) = 0.6 T

    the magnitude of torque = 1.1 N m

    angle = 30°

    we know,

    τ = N I A B sin θ

    θ = is the angle between Area vector and magnetic field so θ = 60°

    1.1 = 1 x 4 x A x 0.6 x sin 60°

    1.1 = 2.078 x A

    A = 0.53 m²

    hence, the correct answer is option B
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