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11 March, 19:03

A projectile was launched horizontally with a velocity of 468m/s, 1.86m above the ground how long did it take the projectile to hit the ground

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  1. 11 March, 20:48
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    0.616 s to 3 significant figures

    Explanation:

    Using the equation s=ut+0.5at^2 in the vertical direction:

    1.86=0*t+0.5gt^2

    1.86=4.905t^2

    t^2=1.86:4.905

    t=0.6157961457

    =0.616 s (3sf)
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