A diver in midair has an angular velocity of 6.0 rad/s and a moment of inertia of 1.2 kg·m2. He then pulls is arms and legs into a tuck position and his angular velocity increases to 12 rad/s. The net external torque acting on the diver is zero. What is his moment of inertia in the tuck position?

Question

Rock

23 December, 22:59

+3

Answers (1)

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Cayden Evans · Answer 1

0.6 kg m²

Explanation:

Angular momentum is conserved.

Iω = Iω

(1.2 kg m²) (6.0 rad/s) = I (12 rad/s)

I = 0.6 kg m²