Ask Question
24 September, 18:15

A baseball pitcher brings his arm forward during a pitch, rotating the forearm about the elbow. If the velocity of the ball in the pitcher's hand is 34.9 m/s (about 78 mph) and the ball is 0.310 m from the elbow joint, what is the angular velocity of the forearm

+2
Answers (1)
  1. 24 September, 19:55
    0
    112.581 rad/s.

    Explanation:

    Angular velocity: This can be defined as the velocity of a body undergoing angular motion. The S. I unit of angular velocity is rad/s.

    From the question, The expression for angular velocity is given as,

    ω = v/r ... Equation 1

    Where ω = angular velocity of the forearm, v = velocity of the ball in the pitcher's hand, r = the distance of the ball from the elbow joint.

    Given: v = 34.9 m/s, r = 0.310 m

    Substitute into equation 1

    ω = 34.9/0.310

    ω = 112.581 rad/s.

    Hence the angular velocity of the forearm = 112.581 rad/s.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A baseball pitcher brings his arm forward during a pitch, rotating the forearm about the elbow. If the velocity of the ball in the ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers