Two 125 kg bumper cars are moving toward each other in opposite directions. Car X is moving at 10 m/s and Car Z at - 12 m/s when they collide head-on. If the resulting velocity of Car Z after the collision is 10 m/s, what is the velocity of Car X after the collision?

-12 m/s

-10 m/s

10 m/s

12 m/s

Question

Trinity Joyce

31 July, 20:58

+5

Answers (1)

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Drake Arroyo · Answer 1

Applying the law of conservation of momentum,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂; m₁ = m₂ so:

u₁ + u₂ = v₁ + v₂

10 - 12 = v₁ + 10

v₁ = - 12 m/s

Two 125 kg bumper cars are moving toward each other in opposite directions. Car X is moving at 10 m/s and Car Z at - 12 m/s when they collide head-on. If the resulting velocity of Car Z after the collision is 10 m/s, what is the velocity of Car X after the collision?-12 m/s-10 m/s10 m/s12 m/s