A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the box?

Question

Physics

Tatiana Yoder

2 October, 13:50

A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the box?

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Answers (1)

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Maverick Roth · Answer 1

Use this numbers that you are given and plug them into the formule for net force

Net force = m*a (mass times acceleration)

Therefore the net force is equal to (5.5 kg) * (4.2 m/s^2) = 23.1 N

Answer: Net force = 23.1 N