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6 December, 21:03

At a pressure 43 kPa, the gas in a cylinder has a volume of 12 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 8 liters, what is the new pressure?

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  1. 6 December, 22:38
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    P = 43 * 10^3

    V = 12 L

    P' = ?

    V' = 8 L

    PV = P'V'

    43*10^3 * 12 = P' * 8

    I know you can do it from here, mate; )
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