A woman pulls on her dog's leash with a force of 65 N directed at an angle of 32° to the horizontal. What is the vertical component of this force? 21 N 55 N 34 N 29 N

Since the angle is 32 to the horizontal: what you have to do is subtract 90 - 32 to get the angle under the leash ...

90 - 32 = 58

Then all you have is a simple trig problem to solve ...

hyp = 65N

vert = x

theta = 58

sin (theta) = vert/hyp

sin (58) = (x/65)

x = 65 (sin (58))

x = vertical component = 55N

Therefore the answer is: B