Calculate the molar solubility of Ni (OH) 2 in water. Use 2.0 * 10^-15 as the solubility product constant of Ni (OH) 2.

Question

Chemistry

Damian Luna

12 May, 10:15

Calculate the molar solubility of Ni (OH) 2 in water. Use 2.0 * 10^-15 as the solubility product constant of Ni (OH) 2.

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Weiner · Answer 1

Ni (OH) ₂ (s) ⇄ Ni²⁺ (aq) + 2OH⁻ (aq)

Ksp=2.0*10⁻¹⁵

Ksp=[Ni²⁺][OH⁻]²

c=[Ni²⁺]=[OH⁻]/2

Ksp=c * (2c) ²=4c³

c=∛ (Ksp/4)

c=∛ (2.0*10⁻¹⁵/4) = 0.01995 mol/L ≈ 0.02 mol/l