A sample of nitrogen goes from 21L to 14L and it's pressure increases from 100kPa to 150kPa. The final temperature is 300K. What was the initial temperature in Kelvins?

Question

Chemistry

Chaim Schaefer

9 February, 17:57

A sample of nitrogen goes from 21L to 14L and it's pressure increases from 100kPa to 150kPa. The final temperature is 300K. What was the initial temperature in Kelvins?

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Answers (1)

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Curtis Wheeler · Answer 1

The initial temperature is 300 K (The temperature doesn't change)

Explanation:

Step 1: Data given

Initial volume = 21L

Final volume = 14L

Initial pressure = 100 kPa = 0.986923 atm

Final pressure = 150 kPa = 1.48038 atm

The final temperature = 300K

Step 2: Calculate the initial temperature

Calculate the initial temperature

(P1*V1) / T1 = (P2*V2) / T2

⇒with P1 = the initial pressure = 0.986923 atm

⇒with V1 = the initial volume = 21 L

⇒ with T1 = the initial temperature = ?

⇒with P2 = the final pressure = 1.48038 atm

⇒with V2 = the final volume = 14 L

⇒with T2 = the final temperature = 300 K

(0.986923 * 21) / T1 = (1.48038*14) / 300

T1 = 300 K

The initial temperature is 300 K (The temperature doesn't change)